Question

9x^2-8x-1. 9 x square - 8 x minus one factorise

Answer 1

$9x {}^{2} - 8x - 1 \\ 9x {}^{2} - 9x + x - 1 \\ 9x(x - 1) + 1(x - 1) \\ (9x + 1)(x - 1) \\ x = - \frac{1}{9} \\ x = 1$

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