Question

9x^2 + 8x + 1 find the zero of the polynomial​

Answer 1

Answer:

9x^2+9x-x+1

9x(x+1)-1(x+1)

(9x-1)(x+1)

9x-1=0 x+1=0

9x=1 x= -1

x=1/9

Answer 2

Answer:

Zeroes are : 1/9 and -1

Step-by-step explanation:

9x^2 + 8x +1

9x^2 + 9x - 1x + 1

9x( X + 1) -1( X + 1)

(9x -1) (X +1)

equating factors to zero

X = 1/9 and X = -1