9x^2+9x=180.find the value of x
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Answered by
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x^2 + x = 20
x^2 + x - 20 = 0
x^2 + 5x - 4x - 20 = 0
x(x+5) - 4(x+5) = 0
(x+5)(x-4) = 0
the values of x are -
-5 , 4
maria9:
please mark my answer as brainliest ... Thank q
Answered by
0
hey mate your answer↓
9x^2+9x-180=0
dividing by 9
x^2+x-20=0
x^2+5x-4x-20=0
x(x+5)-4(x+5)=0
(x+5)(x-4)=0
x=-5 or x=4
hope it helps you!
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