Question

(9x+2)(x+1)=(x+4)(x-2)
quadratic ​

Answer 1

Answer:

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Step-by-step explanation:

By using distributive property :

=> 9x² + 9 + 2x + 2 = x² - 2x - 4x - 8

Put the like terms :

=> 9x²+ x² + 2x - 2x = 9 - 8

=> 10x² = 1

On transposing the terms :

$\red{ {x}^{2} = \frac{1}{10} } \\ \\ x = \boxed{ \green{\sqrt{ \frac{1}{10} } }}$

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i hope it helps you

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Answer 2

(9x+2)(x+1)=(x+4)(x-2)

9x^2 +2x+9x+2 = x^2+4x-2x-8

9x^2-x^2 +2x-4x+2x+2+8=0

8x^2+10=0

this is not in the form of ax^2+bx+c=0

a#0 & b#0