Question

9x ^2+y^2_6xyz+2yz_6zx hence the value when x=1, y=2 z=_1

Answer 1

9x2 + y2 – 6xyz + 2yz – 6zx

• When x = 1 , y = 2, z = -1

• 9(1)2 + 22 – 6 x 1 x 2 x (-1) + 2 x 2 x (-1) – 6 (-1) 1

• 9 + 4 + 12 – 4 + 6

• =27