Question

9x^+24x+16 factories the using identities

Answer 1

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9x^+24x+16 factories the using identities

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$= > 9 {x}^{2} + 24x + 16 = 0$

It is in the form of quadratic equation:-

e.g-->>ax^2+bx+c

=>>16×9=144

we need to think any number when we add makes 24 and when multiply makes 144

so, we think 12 is the suitable number also 144 is a square value of 12.

$= > 9 {x}^{2} + 12x + 12x + 16 = 0$

$= > 3x(3x + 4) + 4(3x + 4) = 0$

=>taking 3x as common as 9 and 12 are multiples of 3 & 4 from other term as 12 and 16 are multiples of 4.

$= > (3x + 4)(3x + 4) = 0$

$\bold{= > x = - \frac{3}{4}}$

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