Question

9x/3+1=7x-4/3

please give answer​

Answer 1

$\huge\underline\mathfrak\purple{Answer}$

$\frac{9x}{3} + 1 = 7x - \frac{4}{3} \\ \\\frac{9x + 3}{ 3} = \frac{21x - 4}{3} \\ \\ 3(9x + 3) = 3(21x - 4) \\ \\ 27x + 9 = 63x - 12 \\ \\ 27x - 63x = - 12 - 9 \\ \\ - 36x = - 21 \\ \\ 36x = 21 \\ \\ x = \frac{21}{36} \\ \\ x = \frac{7}{12}$

⭐hope it helps ⭐

Answer 2

$\huge{\red{\underline {\underline {Question}}}}$

$\frac{9x}{3} + 1 = \frac{7x - 4}{3}$

$[\huge{\red{\underline {\underline {Answer:-}}}}$

= > $x = \frac{7}{12}$

Solution :-

$= > \frac{9x}{3} + 1 = 7x - \frac{ 4}{3}$

$= > \frac{9x}{3} + \frac{3}{3} = \frac{21x - 4}{3}$

$= > \frac{9x + 3}{3} = \frac{21x - 4}{3}$

=> 3(9x+3) = 3(21x-4)

=> 27x + 9 = 63x -12

=> 27x - 63 x = -12-9

=>-36 x = -21

=> 36x = 21

$= > x = \frac{21}{36}$

$= > x = \frac{7}{12}$

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Hope it help you ☺ ✌