Question

9x^4_10x^3+7x^2-20÷x^2+2
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Answer 1

Answer:

$9x {}^{4} \times 10x {}^{3} + 7x {}^{2} - 20 \div x {}^{2} + 2 \\ = 90x {}^{7} + 7x {}^{2} - 20 \div x {}^{2} + 2 \\ = 630x {}^{9} - 20 \div x {}^{2} + 2 \\ = 630x {}^{7} - 20 + 2 \\ = 630x {}^{7} - 18 \\ = 612x {}^{7} .$