Math, asked by sahithit720, 1 month ago

9x + 4y + 162 + 12xy + 16yz + 24zx =
a) (3x + 4y + 2z) b) (3x + 2y + 4z)
c) (2x + 3y + 4z)
d) (3x-2y - 25
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Answers

Answered by conqueror3
1

Answer:

A) (3x + 4y + 2z) b) (3x + 2y + 4z)

Step-by-step explanation:

(3x + 4y + 2z) b) (3x + 2y + 4z)

Answered by divyakumari5945677
3

Answer: 3x + 2y + 4z

Step-by-step explanation:

9x + 4y + 162 + 12xy + 16yz + 24zx =

 {(3x)}^{2}  +  {(2y)}^{2}  +  {(4z)}^{2}    + 2 \times 3x \times 2y + 3 \times 2y \times 4z  + 3 \times 4z \times 3x

 =  {a}^{2}  +  {b}^{2}  +  {c}^{2} + 2ab + 2bc + 2ca = {(a + b + c)}^{2}

 =  {(3x + 2y + 4z)}^{2}

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