9x-5y=2
3x-4y=10
(do it by elimination method)
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Answer:
multiplying eq 1 by 3 and eq 2 by 9
We get
27x-15y=6
27x-36y=90
27x is eliminated on subtracting both the equations
21y=-84
y=-84/21
y=-4
put the value of y in eq 1
9x-5y=2
9x-5*-4=2
9x+20=2
9x=2-20
9x=-18
x=-18/9
x=-2
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