(9x-5y) square+180xy=(9x+5y) square
Answers
Answered by
13
(9x-5y)^2+180xy=(9x+5y)^2
(9x)^2+(5y)^2-2(9x)(5y)+180xy=(9x)^2+(5y)^2+2(9x)(5y)
(9x)^2+(5y)^2-90xy+180xy=(9x)^2+(5y)^2+90xy
(9x)^2+(5y)^2+90xy=(9x)^2+(5y)^2+90xy
(9x)^2+(5y)^2=(9x)^2+(5y)^2+90xy-90xy
(9x+5y)^2=(9x+5y)^2
(9x)^2+(5y)^2-2(9x)(5y)+180xy=(9x)^2+(5y)^2+2(9x)(5y)
(9x)^2+(5y)^2-90xy+180xy=(9x)^2+(5y)^2+90xy
(9x)^2+(5y)^2+90xy=(9x)^2+(5y)^2+90xy
(9x)^2+(5y)^2=(9x)^2+(5y)^2+90xy-90xy
(9x+5y)^2=(9x+5y)^2
Similar questions