Question

9x [(-7) + 3) = (9) x + (9) 3​

Answer 1

Answer:

9×(-7+3)=(9)x+(9)3

9×(-4)=9x+27

-36=9x+27

-36-27=9x

-63=9x

-63/9=x

-7=x

Answer 2

Answer:

$x\left(\left(-7\right)+3\right)=\left(9\right)x+\left(9\right)\cdot \:3\quad :\quad x=-\dfrac{3}{5}\quad \left(\mathrm{Decimal}:\quad x=-0.6\right)$

Step-by-step explanation:

$9x\left(\left(-7\right)+3\right)=\left(9\right)x+\left(9\right)\cdot \:3$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$9x\left(\left(-7\right)+3\right)=9x+9\cdot \:3$

$\mathrm{Multiply\:the\:numbers:}\:9\cdot \:3=27$

$9x\left(\left(-7\right)+3\right)=9x+27$

$\mathrm{Expand\:}9x\left(\left(-7\right)+3\right):\quad -36x$

$-36x=9x+27$

$\mathrm{Subtract\:}9x\mathrm{\:from\:both\:sides}$

$-36x-9x=9x+27-9x$

$\mathrm{Simplify}$

$-45x=27$

$\mathrm{Divide\:both\:sides\:by\:}-45$

$\dfrac{-45x}{-45}=\dfrac{27}{-45}$

$\mathrm{Simplify}$

$\mathrm{Simplify\:}\dfrac{-45x}{-45}:\quad x$

$\mathrm{Simplify\:}\dfrac{27}{-45}:\quad -\dfrac{3}{5}$

$x=-\dfrac{3}{5}$