Question

9x - [8 – (3 - 7x) – 3{5x - 3(4 - 2x)}]​

Answer 1

Step-by-step explanation:

9×-[8-(3-7×)-3{5×-12-6×)}]

9×-[8-(3-7×)-3{5×-6×-12)}]

9×-[8-(3-7×)-3{-×-12)}]

9×-[8-(3-7×)3×+36)]

9×-[8-(3-7×)3×+36

9×-[8-3+7×]3×+36

9×-[8-3+7×]3×+36

9×-[5+7×]3×+36

9×-5-7×+3×+36

9×-7×+3×-5+36

2×+3×+31

5×=31

Answer 2

x=1

Step-by-step explanation:

Given,that

9x-(8-(3-7×)-3(5×-3(4-2×))=0

to find the value of x we should consider whole value should be zero if RHS is not given

then, solve the values in small brackets to make easy calculate

you get,

9×-(8-3+7×)-3(5×-12+6×)=0

then, multiply the values in bracket with the given values

you will get,

9×-8+3-7×-15×+36-18×=0

by that

-31×+31=0

take the +31 to RHS to make it negative

so that it becomes,

-31×=-31

31×=31 (since both nagatives will get canceled as they are one in LHS and other in RHS

finally you get,

x=31÷31

Therfore, ×=1