Question

9x ki power 2 + 8 x minus 6 x ki value hi 1 upon 3​

Answer 1

Answer:

Step-by-step explanation:

What is the snswer given

Answer 2

Step-by-step explanation:

$Given: \: 9 {x}^{2} + 8x - 6x = \frac{1}{ 3} \\ \therefore 9 {x}^{2} + 2x = \frac{1}{3} \\ \therefore \: 27 {x}^{2} + 6x = 1 \\ \therefore \: 27 {x}^{2} + 6x - 1 = 0 \\ \therefore 27 {x}^{2} + 9x - 3x - 1 = 0 \\ \therefore \: 9x(3x + 1) - 1(3x + 1) = 0 \\ \therefore \: (3x + 1)(9x - 1) = 0 \\ \implies \: 3x + 1 = 0 \: or \: 9x - 1 = 0 \\ \implies \: 3x = - 1 \: or \: 9x = 1 \\ \implies \: x = - \frac{1}{3} \: or \: x = \frac{1}{9}$