Math, asked by RiyaOP, 9 months ago

9x square- 16y square *


(3x- 4y) ( 3x- 4y)

(3x+4y) (3y-4x)

(3x-4y) (3x+4y)

None of these​

Answers

Answered by MoodyCloud
18

Answer is (c) part that is

(3x - 4y) ( 3x + 4y)

_________________

Step by step explanation:-

Given equation is 9x²- 16y²

This can be written as

=> (3x)²- (4y)²

  • Because 9 is square of 3 and 16 is of 4 .
  • And same x² is of x and y² is of y.

By using identity

● a²- b² = (a+b)(a-b)

So, by applying this identity in equation it will be ,

=> (3x)²- (4y)²

=> ( 3x - 4y)(3x + 4y )

________________

More identities:-

◆ (a + b)² = (a)²+(b)²+ 2ab

◆ (a - b)² = (a)²+(b)²- 2ab

Answered by BrainlyGod377
0

Answer is (c) part that is

(3x - 4y) ( 3x + 4y)

_________________

Step by step explanation:-

Given equation is 9x²- 16y²  

This can be written as  

=> (3x)²- (4y)²  

  • Because 9 is square of 3 and 16 is of 4 .
  • And same x² is of x and y² is of y.

By using identity

● a²- b² = (a+b)(a-b)

So, by applying this identity in equation it will be ,  

=> (3x)²- (4y)²  

=> ( 3x - 4y)(3x + 4y )

________________

More identities:-  

◆ (a + b)² = (a)²+(b)²+ 2ab  

◆ (a - b)² = (a)²+(b)²- 2ab

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