Question

9x2-12x+2=0 by completing square method

Answer 1

ANSWER:

$9 {x}^{2} - 12x + 2 = 0$

$9 {x}^{2} - 12x = - 2$

${(3x)}^{2} - 2(3x)(2) = - 2$

$adding \: {(2)}^{2} \: on \: both \: sides$

${(3x)}^{2} - 2(3x)(2) + {(2)}^{2} = - 2 + {(2)}^{2}$

$using \: formula \: {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2}$

${(3x - 2)}^{2} = - 2 + 4$

${(3x - 2)}^{2} = 2$

$taking \: square \: root \: on \: both \: sides$

$\sqrt{ ({3x - 2})^{2} } = \frac{ + }{} \sqrt{2}$

$3x - 2 = \frac{ +}{} \sqrt{2}$

$3x = 2 \frac{ + }{} \sqrt{2}$

$x = \frac{2 \frac{ + }{} \sqrt{2} }{3}$

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