9x²-12x+20
Solve it by factorization method ??? Fast plz
![99x {?}^{2} 99x {?}^{2}](https://tex.z-dn.net/?f=99x+%7B%3F%7D%5E%7B2%7D+)
solve this
Attachments:
![](https://hi-static.z-dn.net/files/d9d/e199c623a9666da7162f8ec85b97791c.jpg)
Answers
Answered by
1
Solving for the question in the attachment..
6m²-11mn-10n²
=6m²-15mn+4mn-10n²
=3m(2m-5n)+2n(2m-5n)
=(2m-5n)(3m+2n)=0
2m-5n=0 or 3m+2n=0
Now, for the question you wrote....
I can't find or factorise it.. there must be a mistake!!! Give this question a view...
if 9x²-11x-20 is the question...
9x²-20x+9x-20
9x(x+1)+20(x+1)
so, (9x+20)=0 or (x+1)=0!
6m²-11mn-10n²
=6m²-15mn+4mn-10n²
=3m(2m-5n)+2n(2m-5n)
=(2m-5n)(3m+2n)=0
2m-5n=0 or 3m+2n=0
Now, for the question you wrote....
I can't find or factorise it.. there must be a mistake!!! Give this question a view...
if 9x²-11x-20 is the question...
9x²-20x+9x-20
9x(x+1)+20(x+1)
so, (9x+20)=0 or (x+1)=0!
Similar questions