Question

9x2-12x+4 find the zero of the polynomial​

Answer 1

Answer:

${9x}^{2} - 12x + 4 \\ = {9x}^{2} - 6x - 6x + 4 \\ = 3x(3x - 2) - 2(3x - 2) \\ = (3x - 2)(3x - 2) \\ so \:zeroes \: are \: \frac{2}{3}$

Answer 2

Answer:

$9 {x}^{2} - 12x + 4 \\ 9x {}^{2} - 6x - 6x + 4 \\ 3x(x - 2) + 2(x - 2) \\ (3x + 2)(x - 2)$

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