Math, asked by varisha24, 1 year ago

(9x² - 16x - 4) -(15x -12x²+5)​

Answers

Answered by AbhijithPrakash
20

Answer:

\blue{\left(9x^2-16x-4\right)-\left(15x-12x^2+5\right)=21x^2-31x-9}

Step-by-step explanation:

\left(9x^2-16x-4\right)-\left(15x-12x^2+5\right)

\gray{\mathrm{Remove\:parentheses}:\quad \left(a\right)=a}

=9x^2-16x-4-\left(15x-12x^2+5\right)

\black{-\left(15x-12x^2+5\right):}

\gray{\mathrm{Distribute\:parentheses}}

=-\left(15x\right)-\left(-12x^2\right)-\left(5\right)

\gray{\mathrm{Apply\:minus-plus\:rules}}

\gray{-\left(-a\right)=a,\:\:\:-\left(a\right)=-a}

=-15x+12x^2-5

=9x^2-16x-4-15x+12x^2-5

\black{\mathrm{Simplify}\:9x^2-16x-4-15x+12x^2-5:}

9x^2-16x-4-15x+12x^2-5

\gray{\mathrm{Group\:like\:terms}}

=9x^2+12x^2-16x-15x-4-5

\gray{\mathrm{Add\:similar\:elements:}\:-16x-15x=-31x}

=9x^2+12x^2-31x-4-5

\gray{\mathrm{Add\:similar\:elements:}\:9x^2+12x^2=21x^2}

=21x^2-31x-4-5

\gray{\mathrm{Subtract\:the\:numbers:}\:-4-5=-9}

=21x^2-31x-9


Anonymous: Awesome : )
AbhijithPrakash: Thank You!!! :)
Answered by raginic1981
5

Answer:

9x² -16x - 4

-12ײ+15x+ 5

(+) (-) (-)

___________

21x² -31x -9

___________

Step-by-step explanation:

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