Math, asked by lakshmilohithn, 7 months ago

9x2+18x+5 factorise by using factor theorem

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Answered by priyanka0506

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${9x}^{2} + 18x + 5 \\ we \: need \: to \: put \: 3 \: and \: 15 \: in \: the \: middle \\ because \: 3 \times 15 = 45 \\ and \: \: 3 + 15 = 18$

${9x}^{2} + 3x + 15x + 5 = 0 \\ taking \: common \: one \: out \\ 3x(3x + 1) + 5(3x + 1) = 0 \\ (3x + 5)(3x + 1) = 0 \\ (3x + 5) = 0 \: \: and \: (3x +1 ) = 0 \\ 3x = - 5 \: \: and \: 3x = - 1 \\ x = \frac{ - 5}{3} \: \: and \: x = \frac{ - 1}{3}$

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Answered by jyotsna26

Answer:

9x^2+18x+5=0

Step-by-step explanation:

9x^2+3x+15x+5=0

3x(3x+1)+5(3x+1)=0

(3x+5)(3x+1)=0

3x=(-5)

x=(-5/3)

3x=(-1)

x=(-1/3)

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9x2+18x+5 factorise by using factor theorem​

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x=(-5/3)

x=(-1/3)

9x2+18x+5 factorise by using factor theorem