Question

9x²+19x+8 factorise it​

Answer 1

Mate I think it will

$\ {9x^2+18x+8}$

$\underline{Solution:-}$

$\ {=>9x^2+12x+6x+8}$

$\ {=>3x(3x+4) +2(3x+4)}$

$\ {=>(3x+4)(3x+2)}$

$\ {=>(3x+4)=0 or (3x+2)=0}$

$\ {X= -4/3 or X= -2/3}$

•°• Value of the X will be $\ {-4/3\: or -2/3}$

Answer 2

9x² + 18x + 8

________ [GIVEN EQUATION]

• We have to find the factors of it.

_______________________________

9x² + 18x + 8

The above equation is in the form ax² + bx + c.

So.. we have to find the the numbers whose sum is b and product is c.

12 and 6 are the correct numbers because sum of 12 and 6 is 18 which is b and product of 12 and 6 is 72 which is c.

=> 9x² + 12x + 6x + 8 = 0

=> 3x (3x + 4) +2 (3x + 4) = 0

=> (3x + 2) (3x + 4) = 0

• 3x + 2 = 0

=> 3x = - 2

=> x = $\dfrac{-2}{3}$

• 3x + 4 = 0

=> 3x = - 4

=> x = $\dfrac{-4}{3}$

______________________________

x = $\dfrac{-2}{3}$ and $\dfrac{-4}{3}$

___________ [ANSWER]

______________________________