Question

9x2 - 6px + (p2 - q2) = 0

Answer 1

Answer:

value of x = (p+q)/3 or (p-q)/3

Step-by-step explanation:

given that :

9x² - 6px + (p² - q²) = 0

the above equation can be solved using

x =x= [ -(-6p)−(−6p) ± \sqrt{(-6p)^2 - 4(9)(p^2-q^2)}

(−6p)

2

−4(9)(p

2

−q

2

)

] ÷ 2(9) ⇒ eq1

this is the most fundamental formula for solving x which is as

x = -bx=−b ± \sqrt{b^2-4ac}

b

2

−4ac

÷ (2a)

where a = 9 ; b = (-6p) ; c = (p^2-q^2)a=9;b=(−6p);c=(p

2

−q

2

) from the general equation

ax^2 + bx + c =0ax

2

+bx+c=0

from eq 1 ;

x = [ 6p ± \sqrt{36p^2-36p^2+36q^2}

36p

2

−36p

2

+36q

2

] ÷ (18)

x = [ 6p ± 6q ] ÷ 18

x = [p ± q ] ÷ 3

x = (p+q)/3 or (p-q)/3