9x2-6x+1 find the relation between the zeros and coefficient of Quadratic polynomial
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9x² - 6x + 1
= (3x -1)²
∴3x-1 = 0
x = 1/3
∴α = 1/3 ∴β = 1/3
9x² - 6x + 1
ax² + bx + c
∴ a = 9
b = -6
c = 1
αβ =(1/3)(1/3) = 1/9 = a/c
α+β =(1/3)+(1/3) = 2/3= 6/2 = -b/a
Hence verified
= (3x -1)²
∴3x-1 = 0
x = 1/3
∴α = 1/3 ∴β = 1/3
9x² - 6x + 1
ax² + bx + c
∴ a = 9
b = -6
c = 1
αβ =(1/3)(1/3) = 1/9 = a/c
α+β =(1/3)+(1/3) = 2/3= 6/2 = -b/a
Hence verified
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