9x2-kx+16 if root are same find the value of k
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Hence a = 9,b=8k and c = 16
0=(8k)^2 -4*9*16
0=64k^2-576
0=(tex)k^[2]=9
K=3
0=(8k)^2 -4*9*16
0=64k^2-576
0=(tex)k^[2]=9
K=3
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