Question

9x³y³-14xy+20/(xy+5)​

Answer 1

Answer:

According to question,

(9x3y3−14xy+20)÷(xy+5)

xy+59x3y3−14xy+20​

⟹xy+5(xy+5)(9x2y2−45xy)+211xy+20​

⟹9x2y2−45xy+xy+5211xy+20​

It is not completely divisible,

Hencr remainder is  211xy+5