9xsquare - 3x-2
![9x2 - 3x - 2 = 0 9x2 - 3x - 2 = 0](https://tex.z-dn.net/?f=9x2+-+3x+-+2+%3D+0)
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Hi mate your answer is...
9x^2-3x-2=0
9x^2-(6-3) x-2=0
9x^2-6x+3x-2=0
3x(3x-2) +1(3x-2) =0
(3x+1) (3x-2)
Then the value of x=-1/3 and 2/3
I hope it will help you...
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