Question

9xsquare-9(a+b) x+2(2asquare+5ab+2bsquare) = 0

Answer 1

9x2 - 9(a + b) x + (2a2+ 5ba + 2b2) = 0

9x2 - 9(a + b)x + (2a + b) (a + 2b) = 0

9x2 - 3(2a + b)x - 3 (a + 2b)x + (2a + b) (a + 2b) = 0

3x[3x - (2a + b)] - (a + 2b) [3x - (2a + b)] = 0

[3x - (2a + b)] [3x - (a + 2b)] = 0

x =

hope this helps