9y^2-12y+2=0solveby completing method
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Hey Mate ✌
Here's your answer friend,
By completing the square method ⏩
==> 9y² - 12y + 2= 0
==> Divide the whole equation by 9 (coefficient of x2)
we get,
==> y² - 4y/3 + 2/9
==> y² -4y/3 = -2/9
Now third term ==> (1/2 X coefficient of x )²
==> (1/2 X -4/3)²
==> (-2/3)²
Now adding third term to both LHS and RHS
we get,
y² - 4y/3 + (-2/3)² = -2/9 + (-2/3)²
==> (y - 2/3)² = -2/9 + 4/9
.............{by using the identity a² -2ab + b² = (a + b)²}
==> (y - 2/3)² = 2/9
==> Now taking square root on both the sides
we get,
==> √(y - 2/3)² = √2/√9
==> y - 2/3 = √2/3
==> y = √2 + 2 / 3
is the required answer.
⭐ Hope it helps you ^_^ ⭐
Here's your answer friend,
By completing the square method ⏩
==> 9y² - 12y + 2= 0
==> Divide the whole equation by 9 (coefficient of x2)
we get,
==> y² - 4y/3 + 2/9
==> y² -4y/3 = -2/9
Now third term ==> (1/2 X coefficient of x )²
==> (1/2 X -4/3)²
==> (-2/3)²
Now adding third term to both LHS and RHS
we get,
y² - 4y/3 + (-2/3)² = -2/9 + (-2/3)²
==> (y - 2/3)² = -2/9 + 4/9
.............{by using the identity a² -2ab + b² = (a + b)²}
==> (y - 2/3)² = 2/9
==> Now taking square root on both the sides
we get,
==> √(y - 2/3)² = √2/√9
==> y - 2/3 = √2/3
==> y = √2 + 2 / 3
is the required answer.
⭐ Hope it helps you ^_^ ⭐
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