Question

9y-29=5y+15

Liner equation and inequations

Answer 1

9y-29=5y+15

-> 9y-5y=15-(-29)

-> 4y=15+29=44

-> y=44/4

=11

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Answer 2

Answer:

We get the value of y$=11$

Step-by-step explanation:

In accordance with the information provided in the question,

We have find the value of the supplied expression in the above question.

Given the data in question 9y-29=5y+15

Here we will use the transposition method.

Hence, for solving the above equation, we will solve it by separating the like terms at one side to another side,

So, we will shift 29 from LHS to RHS the sign will change from negative to positive,

So, we will shift 5y from RHS to LHS the sign will change from positive to negative,

As we get,

$9y-29=5y+15\\9y-5y=15+29\\4y=44$

Divide both side by 4 we get,

$\frac{4y}{4} =\frac{44}{4} \\y=11$

Hence the value of y $=11$