Math, asked by lakshaypratap35, 1 year ago

9y2-66yz+121z2 factorisation of 9th standard

Answers

Answered by nikhil400
30
this is your answer .......
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Answered by REDRAGON
23
9y^2-66yz+121z^2

= (3y)^2 - 2 * 3 * 11 + (11z)^2

as u can see, this expression is in the form of (a - b)^2 = a^2 - 2ab + b^2
where, a = 3y and b = 11z

hence, as per the identity , your answer is ,

(3y - 11z)^2 or,
(3y - 11z)(3y - 11z)
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