Question

9z-13=11z+27 slove the equation and check also

Answer 1

given :- 9z-13=11z+27
solution:- by transposition method :-
9z-11z=27+13
-2z=40
so, z = -40/2. ( as subtraction sign NEVER remains
I.e z= -20 in the denominator)

Answer 2

Given :

9z-13=11z+27

To Find :

solve the equation and check also

Solution:

Given equation :$9z-13=11z+27$

$\Rightarrow 9z-13=11z+27\\\Rightarrow 27-13=11z-9z\\\Rightarrow 14=2z\\\Rightarrow \frac{14}{2}=z\\\Rightarrow 7=z$

Substitute the value in equation :

9z-13=11z+27

9(7)-13=11(7)+27

50=50

Thus verified

Hence The value of z is 50