A 0.0020 M aqueous solution of an ionic
compound Co(NH3
)5
(NO2
)Cl freezes at
– 0.00732ºC. Number of moles of ions which 1
mole of ionic compound produces on being
dissolved in water will be
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Answer:
Depression in freezing point (ΔT
f
) is given by,
ΔT
f
=i×K
f
×m
where,
i=Van't Hoff Factor
i=1+α(n−1) for dissociation,
K
f
=Cryoscopic Constant
(For water value of K
f
=1.86)
m=molality of solution
Here ΔT
f
=0−(−0.00732)=0.00732
i=
K
f
×m
ΔT
f
=
1.86×0.0020
0.00732
=1.86≈2
So, This compound, [Co(NH
3
)
5
(NO
2
)]Cl in solution will dissociate into Cl
−
and [Co(NH
3
)
5
(NO
2
)]
+
,n=2
Therefore two moles of ions are formed.
Explanation:
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