Question

A 0.01 m aqueous solution of the alcl3 freezes at -0.068 calculated the percentage of dissociation

Answer 1

Explanation:

Dissolution is the process where a solute in gaseous, liquid, or solid phase dissolves in a solvent to form a solution. Solubility. Solubility is the maximum concentration of a solute that can dissolve in a solvent at a given temperature.Apr 29, 2019

Answer 2

The percentage of dissociation is : 88.5 %

• Given,  Molality of the solution = 0.01
• Depressed freezing point of the solution = -0.068 C
• Also the actual freezing point of the solution = 0 C
• Kf for water = 1.86 C/m
• Now we know, Depresssion is freezing point is given as,
• dT = Kf*i*m    ,  where i = VantHoff factor.
• 0-(-0.068) = 1.86*i*0.01
• i = 0.068 / 1.86 * 0.01  =  0.068 / 0.0186 =  3.656
• Now we know number of ions formed on dissociation of AlCl3 = 4
• Also, i = 1 + α (n-1)  ,   3.656 = 1 + α (4-1)
• 3.656 = 1 + 3α,  3α = 2.656,  α = 0.885
• Now the degree of dissociation = 0.885
• This implies the percentage of dissociation = 88.5%