(a-0.1) (a+0.1)solve
Answers
Answered by
15
it is an identity-
(a-b)(a+b)=a^2+b^2
so....(a-0.1)(a+0.1)=(a)^2+(0.1)^2
=a^2+0.01
(a-b)(a+b)=a^2+b^2
so....(a-0.1)(a+0.1)=(a)^2+(0.1)^2
=a^2+0.01
std9:
most welcome
Answered by
2
Answer:
hope it's help you plz give me thanks
Attachments:
Similar questions