Question

A 0.1 kg pool ball traveling 2.5 m/s hits another 0.1 kg at rest. If the first ball stops after the elastic collision, how fast is the second now moving?
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Answer 1

Explanation:

m1u1+m2u2 = m1v1 +m2v2

0.1(2.5) + 0.1(0) = 0.1(0) + 0.1(v2)

v2 = 2.5 m/sec