Chemistry, asked by parthagarwal311, 1 year ago

A 0.1 m solution of hf is 8% dissociated thn ka for hf is

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Answered by ans81
2
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Answered by Anonymous
2

HF(aq) <=> H+(aq) + F-(aq)


Percent ionization = ([H+]/[HF]) x 100%


8= ([H+]/0.1 M) x 100


(8) (0.1)/100 = [H+]


0.008 M = [H+]


pH = -log[H+] = -log (0.008) = 2.09

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