Chemistry, asked by roshanimranshepc4i3f, 7 months ago

A 0:1 m solution of K2S04 in water has
freezing point of -4.3°c. what is there
of Van't Hoff Factor It Kf for water
Is 1.86 K. Kgmolpower-1

Answers

Answered by shubham0204
20

Answer:

See below.

Explanation:

We are given a 0.1 molal solution of K2SO4 and its freezing point. Using the equation,

\Delta T_{f}=iK_{f}m

The change in freezing point of solvent is ( 0 - ( - 4.3 ) ) = 4.3 Celsius.

\begin{aligned}4.3=i\left( 1.86\right) \left( 0.1\right) \\ i=2\end{aligned}

Note: The answer will be 2 and not 2.311 by rules of significant figures.

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