Chemistry, asked by harsh638580, 3 months ago

A 0.10-L container holds 3.0 x 10^20 molecules of H2 at 100 kPa and OC. If the volume of a hydrogen molecule is 6.7 x 10^-24 mL, what percentage of the volume of the gas is occupied by its molecules?​

Answers

Answered by lucky143424
0

Answer:

Hello

Radius of hydrogen atom, r = 0.5 Å = 0.5 × 10-10 m

Volume of hydrogen atom = (4/3) π r3

= (4/3) × (22/7) × (0.5 × 10-10)3

= 0.524 × 10-30 m3

Now, 1 mole of hydrogen contains 6.023 × 1023 hydrogen atoms.

∴ Volume of 1 mole of hydrogen atoms, Va = 6.023 × 1023 × 0.524 × 10–30

= 3.16 × 10–7 m3

Molar volume of 1 mole of hydrogen atoms at STP,

Vm = 22.4 L = 22.4 × 10–3 m3

V

a

V

m

=

3.6×10

−7

22.4×10

−3

=7.08×10

4

Hence, the molar volume is 7.08 × 104 times higher than the atomic volume.

The ratio is so large because inter-atomic separation in hydrogen gas is large.

Explanation:

Hope it helps you a lot

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