Question

A 0.1m solution of monobasic acid at specific resistance of r ohms-cm, it's molar conductivity is

Answer 1

Hello Dear.

In the Question, there is little typing error. unit of 0.1 is not m but it is M.

Here is the answer---

Before discussing about the Numerical, we must know what is molar conductivity.
∴ Molar Conductivity is defined as the Conductivity of an Electrolytic Solution per unit of the Molarity of the Electrolytes.

Now, Solving is shown below,

Given ⇒
Molarity = 0.1 M.
Specific Resistance or Resistivity(ρ) = r Ω cm.

We know, 
Specif Resistance(ρ) = 1/Conductivity(σ)
∴ Conductivity(σ) = 1/Specific Resistance(ρ)
∴ Conductivity(σ) = 1/r   Ω⁻¹ cm⁻¹

Now,
∵ Solution is of Mono basic Acid,
∴ Molarity = Normality.


We know the Formula,
  Molar Conductivity = Conductivity(σ)/Molarity
∴ Molar Conductivity = (1/r) ÷ 0.1
∴ Molar Conductivity = 1/0.1r
⇒ Molar Conductivity = 10/r  seimens/m M

Hence, Molar Conductivity of the Solution is 10/r Ω⁻¹m⁻¹/M


Hope it helps.

Answer 2

Answer:10 raised to power 4 /r

Explanation: so explanation is that

• formula of molar conductivity is k ×1000/molarity
• here molarity is given 0.1 M but k is not given

to calculate k here specific resistance is given r

conductivity is 1/specific resistance so , k is 1/r .put this in formula

1/r ×1000 completed divided by 0.1 M [molarity] ...so solution comes out to be 10∧4/r

thanku

hope it helps