Question

A 0.2 kg ball is thrown vertically upwards with an initial velocity of 20m/s. What is its momentum when it is halfway to its maximum height? Who can solve it?

Answer 1

Answer:

4 kgm/s

Explanation:

momentum = mass*velocity

p=mv

m=0.2kg

v=20m/s

put the value

p=0.2kg * 20m/s

p=4 kgm/s

momentum =4 kilogram meter per second

Answer 2

Given,

u=20m/s

a=-10m/s

At the highest position, the velocity of ball is zero.Considering it, let us take v=0

Since,

v=u + at,

0=20+(-10)*t

10t=20

t=2s

Now, let us take out the maximum height.

Since,

s=u*t + 1/2*a*t*t

s=20 * 2 + 1/2 * (-10) * 2 * 2

s=40-20

s=20m

Therefore,

halfway the maximum height=20/2=10m

Since,

v1*v1=u*u + 2as ( v1 is the velocity halfway)

Therefore,

v1*v1=20*20+2*(-10)*10

v1*v1=400-200=200

v1=√200=10√2

Therefore,

Momentum=0.2kg * 10√2m/s

=2√2 kg m/s