A 0.20kg mass attached to the end of a spring is whirled in a vertical circle by a student. At some positions,the mass experiences a downward force of --62jN and a horizontal force 38iN. Determine its acceleration in this position.
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Answer:
363.5 m/s²
Explanation:
F=√62²+38²=72.7 N
a=F/m
72.2÷0.20=363.5 m/s²
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