Question

A 0.24 - g sample of a compound of oxygen and boron wss found by analysis to contain 0.096 g of boron and 0.144g of oxygen . Calculate the percentage composition of the compound by the weight

Answer 1

Percentage of boron=0.096×100/0.24

=40℅

Percentage of oxygen=0.144×100/0.24

=60℅

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Answer 2

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☺ Hello mate__ ❤

◾◾here is your answer.

Mass of boron = 0.096g

Mass of oxygen = 0.144g

Mass of sample = 0.24g

Thus, percentage of boron by weight in the compound =( 0.0960 × 100)/0.24 = 40%

Thus, percentage of oxygen by weight in the compound = (0.144× 100)/ 0.24 = 60 %

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I hope, this will help you.☺

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