A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.
Answers
Answer:
Explanation:
Mass of the given sample compound = 0.24g
Mass of boron in the given sample compound = 0.096g
Mass of oxygen in the given sample compound = 0.144g
% composition of compound = % of boron and % of oxygen
Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100
= 40%
Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100
= 60%
Answer:
Total mass of the compound = 0.24g
Mass of Oxygen = 0.144g
So, Percentage of Oxygen Composition = (Mass of Oxygen / Total Mass) x 100%
= (0.144/0.24)x100%
= 0.6x100%
= 60%
So, Percentage of Boron composition = 100% - Oxygen Composition
= 100% - 60%
= 40%