A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by mass.
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@ShiningBlossom
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Mass of the given sample compound = 0.24g
Mass of boron in the given sample compound = 0.096g
Mass of oxygen in the given sample compound = 0.144g % composition of compound = % of boron and % of oxygen
Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100
= 40%
Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100
= 60%
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