A 0.24 g sample of compounds of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen.Calculate the percentage composition of the compound by weight
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total mass of compounds-0.24 g
mass of boron in it=0.096g
therefore% composition by weight of boron =(Mass of boron/Total mass of compounds)*100
=(0.096/0.24)*100
=40%
mass of oxygen in the compound
=(0.144/0.24)*100
=60%
the compound is made up only boron and oxygen, therefore the %Composition of the components sum t 100%(60%+40%)
Explanation:
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