A 0.24 gram sample of compound of Oxygen and Boron was found by analysis to contain 0.096 gram of Boron and 0.144 gram of Oxygen. Calculate the percentage composition of Boron and Oxygen in that compound by weight.
Answers
Answer:
Explanation:
Mass of the given sample compound = 0.24g
Mass of boron in the given sample compound = 0.096g
Mass of oxygen in the given sample compound = 0.144g
% composition of compound = % of boron and % of oxygen
Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100
= 40%
Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100
= 60%
Answer:
Mass of the given sample compound = 0.24g
Mass of boron in the given sample compound = 0.096g
Mass of oxygen in the given sample compound = 0.144g
% composition of compound = % of boron and % of oxygen
Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100
= 40%
Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100
= 60%
Explanation: