a 0.24g sample of a compound of oxygen boron was found by analiyse to contain 0.096g of boron and 0.144g of oxygen . calculate the %composition of by weight. find the number of more in 0.144g of oxygen gas
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Compound = 0.24g
Oxygen = 0.144g
Boron = 0.096g
Percentage of Oxygen = 0.144/0.24 X 100 = 60%
Percentage of Boron = 0.096/0.24 X 100 = 40%
Oxygen = 0.144g
Boron = 0.096g
Percentage of Oxygen = 0.144/0.24 X 100 = 60%
Percentage of Boron = 0.096/0.24 X 100 = 40%
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