A 0.24g sample of compound of oxygen and boron was found by analysis to contain 0.096g of boron and 0.144g of oxygen . calculate the percentage composition of the compound by weight
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Answered by
10
Answer:
40% boron and 60% Oxygen
Explanation:
percentage composition= .096/.24=40 for boron
and .144/.24 =60 for oxygen
Answered by
4
%of O=(0.144/0.24)100=60%
AND OF BORON=100%-60%=40%
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