Question

.A 0.24g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 of oxygen . calculate the percentage composition of the compound by mass .​

Answer 1

$\huge\yellow{\underline{Answer}}$

(1) Mass of boron in compound =0.096g

and , Mass of compound = 0.24g

so , percentage of boron in compound

$= \frac{mass \: of \: boron \: in \: compound}{mass \: of \: compund}$

$\frac{0.144}{0.24} \times 100$

(2) Mass of oxygen in compound = 0.144

Mass of compound = 0.24

so, Percentage of oxygen in compound

$= \frac{mass \: of \: oxygen \: in \: compound}{mass \: of \: compound}$

$\frac{0.144}{0.24}$

$\huge\yellow{\underline{=60Answer}}$