Chemistry, asked by ay9570295amanyadav, 5 months ago

A 0.24g sample of compound of Oxygen and boron was found by analysts to content 0.096g of boron and 0.144 g of Oxygen . calculate the percentage composition of the compound by weight​

Answers

Answered by akankshakamble6
2

Answer:

Mass of compound = 0.24 g and,

mass of boron = 0.096 g

percentage of boron in the compound = mass of boron / mass of compound * 100

= 0.096/0.24 * 100 = 40%

mass of oxygen = 0.144 g again, mass of compound = 0.24 g

percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60%

Explanation:

Mass of the given sample compound = 0.24g

Mass of boron in the given sample compound = 0.096g

Mass of oxygen in the given sample compound = 0.144g

% composition of compound = % of boron and % of oxygen

Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100

= 40%

Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100

= 60%

Answered by bantisaw01
1

Answer:

same as written above............

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