A 0.24g sample of compound of Oxygen and boron was found by analysts to content 0.096g of boron and 0.144 g of Oxygen . calculate the percentage composition of the compound by weight
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Answer:
Mass of compound = 0.24 g and,
mass of boron = 0.096 g
percentage of boron in the compound = mass of boron / mass of compound * 100
= 0.096/0.24 * 100 = 40%
mass of oxygen = 0.144 g again, mass of compound = 0.24 g
percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60%
Explanation:
Mass of the given sample compound = 0.24g
Mass of boron in the given sample compound = 0.096g
Mass of oxygen in the given sample compound = 0.144g
% composition of compound = % of boron and % of oxygen
Therefore % of boron = (mass of boron)/(mass of the sample compound) x 100
= 40%
Therefore % of oxygen = (mass of oxygen) / (mass of the sample compound) x 100
= 60%
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Answer:
same as written above............
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